SOLUTION: Two cyclists leave towns 240 km apart at the same time and travel toward each other. One cyclist travels 4km/h faster than the other. If they meet in 5 hours, what is the rate of e

Question 1111973: Two cyclists leave towns 240 km apart at the same time and travel toward each other. One cyclist travels 4km/h faster than the other. If they meet in 5 hours, what is the rate of each cyclist?
Rate of fast cyclist:_____
Rate of slow cyclist:_____
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Two cyclists leave towns 240 km apart at the same time and travel toward each other. One cyclist travels 4km/h faster than the other. If they meet in 5 hours, what is the rate of each cyclist?
Distance = 240 km
slow cyclist speed = x
fast cyclist speed = (x+4)
travel toward each
add up speed
= x+x+4 -> 2x+4
t= d/s
5 =240/(2x+4)
5(2x+4)=240
10x+20 =240
10x=220
x=22
Rate of fast cyclist:26 km/h
Rate of slow cyclist:22 km/h
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