.
ax + by + c = 0 (1)
bx + ay + c = 0 (2)
Equivalently
ax + by = -c (3)
bx + ay = -c (4)
Multiply eq(3) by b (both sides). Multiply eq(4) by a (both sides). You will get
abx + b^2y = -bc (5)
abx + a^2y = -ac (6)
Subtract (5) from (6). In this way, you eliminate "x" :
(a^2 - b^2)y = -c*(a-b) ====> y = = = // cancel (a-b) // = .
What I did is: I started from (3),(4) and eliminated x; in this way I got y.
Now YOU return to (3),(4); eliminate y and get x.
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You may find these lessons useful to you:
- Solution of the linear system of two equations in two unknowns by the Substitution method
- Solution of the linear system of two equations in two unknowns by the Elimination method
- Solution of the linear system of two equations in two unknowns using determinant
- Geometric interpretation of the linear system of two equations in two unknowns
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".
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Free of charge online textbook in ALGEBRA-I
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to your archive and use it when it is needed.