SOLUTION: Solve ax+by+c=0 and bx+ay+c=0 by the elimination method, thanks.

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Question 1111880: Solve ax+by+c=0 and bx+ay+c=0
by the elimination method, thanks.

Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.
ax + by + c = 0     (1)
bx + ay + c = 0     (2)


Equivalently

ax + by = -c        (3)
bx + ay = -c        (4)


Multiply eq(3) by b (both sides).  Multiply eq(4) by a (both sides).  You will get


abx + b^2y = -bc    (5)
abx + a^2y = -ac    (6)


Subtract (5) from (6). In this way, you eliminate "x" :


(a^2 - b^2)y = -c*(a-b)  ====>  y =   =  = // cancel (a-b) // = .


What I did is: I started from (3),(4) and eliminated x; in this way I got y.


Now  YOU  return to (3),(4);  eliminate y and get x.

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You may find these lessons useful to you:
    - Solution of the linear system of two equations in two unknowns by the Substitution method
    - Solution of the linear system of two equations in two unknowns by the Elimination method
    - Solution of the linear system of two equations in two unknowns using determinant
    - Geometric interpretation of the linear system of two equations in two unknowns

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


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