h = the hundreds digit t = the tens digit u = the units (or ones) digit 100h + 10t + u = the number "HTU" 100u + 10t + h = the number "UTH" with the digits at the hundreds and units places interchanged the sum of digits of a three-digit number is 15.The digit at tens place is half of the sum of digits at hundreds and units places. If 396 is added to the number, the digits at hundreds and units places are interchanged. Find the number. Can you solve the system of those three equations? Edwin