SOLUTION: Suppose that the manufacturer of a DVD player has found​ that, when the unit price is p​ dollars, the revenue R​ (in dollars) as a function of the price p is R(

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Question 1109607: Suppose that the manufacturer of a DVD player has found​ that, when the unit price is p​ dollars, the revenue R​ (in dollars) as a function of the price p is
R(p)=-2.5p^2+850p
​(a) For what price will the revenue be​ maximized?
​(b) What is the maximum​ revenue?

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
R=-2.5p^2+850 p
This is a quadratic where the vertex is the maximum value.
vertex p value is -b/2a=-850/-2.5*2=+170 so $170 is price at maximum revenue
R=-2.5*170^2+850*170
=-72250+144500
=$72,250

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