SOLUTION: The length of a rectangle is
2
ft
longer than its width.
If the perimeter of the rectangle is
36
ft
, find its area.
Algebra.Com
Question 1100521: The length of a rectangle is
2
ft
longer than its width.
If the perimeter of the rectangle is
36
ft
, find its area.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Width=x
length=x+2
perimeter=2(width)+2(length)=36
2x+2x+4=36
4x+4=36
4x=32
x=8 feet width
x+2=10 feet length.
Area is length*width=80 ft^2.
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