SOLUTION: Latoya, Miguel, and Deon have a total of
$108
in their wallets. Deon has
4
times what Miguel has. Latoya has
$6
less than Miguel. How much does each have?
LaToya =
Algebra.Com
Question 1096864: Latoya, Miguel, and Deon have a total of
$108
in their wallets. Deon has
4
times what Miguel has. Latoya has
$6
less than Miguel. How much does each have?
LaToya = L
Miguel = M
Deon = D
L + M + D = 108
D = 4M
L = M - 6
M - 6 + M + 4M = 108
6M - 6 = 108
6M = 108 + 6
6M = 114
M = 19
D = 4 x 19
D = 76
L + 19 + 76 = 108
L + 95 = 108
L = 108 - 95
L = 13
LaToya = $13
Miguel = $19
Deon = $76
Found 2 solutions by josh_jordan, ikleyn:
Answer by josh_jordan(263) (Show Source): You can put this solution on YOUR website!
LaToya = L
Miguel = M
Deon = D
L + M + D = 108
D = 4M
L = M - 6
M - 6 + M + 4M = 108
6M - 6 = 108
6M = 108 + 6
6M = 114
M = 19
D = 4 x 19
D = 76
L + 19 + 76 = 108
L + 95 = 108
L = 108 - 95
L = 13
LaToya = $13
Miguel = $19
Deon = $76
Answer by ikleyn(52887) (Show Source): You can put this solution on YOUR website!
.
Your solution is correct.
Good job !
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