SOLUTION: a boat traveled 336 miles downstream and back. The trip downstream took 12 hours. The trip back took 14 hours. what is the speed of the boat in still water? What is the speed of th
Question 1095948: a boat traveled 336 miles downstream and back. The trip downstream took 12 hours. The trip back took 14 hours. what is the speed of the boat in still water? What is the speed of the current? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
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a boat traveled 336 miles downstream and back. The trip downstream took 12 hours. The trip back took 14 hours.
what is the speed of the boat in still water? What is the speed of the current?
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Let u be the motorboat speed in still water and v be the current rate.
The effective speed going downstream is
= = 28 miles per hour.
It is the SUM of the motorboat speed in still water and the rate of the current. It gives you your first equation
u + v = 28. (1)
The effective speed going upstream is
= = 24 miles per hour.
It is the DIFFERENCE of the motorboat speed in still water and the rate of the current. It gives you your second equation
u - v = 24. (2)
Thus you have this system of two equations in 2 unknowns
u + v = 28, (1) and
u - v = 24. (2)
Add the two equations. You will get
2u = 28 + 24 = 52 ====> u = = 26 mph.
So, you just found the speed of the motorboat in still water. It is 26 mph.
Then from the equation (1) you get v = 28 - 26 = 2 mph is the current rate.
Answer. The speed of the motorboat in still water is 26 mph.
The current rate is 2 km/h.
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