Question 1093769: In his will, a man left his older son $5,000 more than twice as much as he left his younger son. If the estate is worth $700,000, how much did the younger son get?
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! if you let x represent what he left the younger son, then:
2x + 5000 represents what he left the older son.
the sum must be equal to 700,000, so x + 2x + 5000 = 700,000.
combine like terms and subtract 5000 from both sides of this equation to get:
3x = 695,000.
solve for x to get x = 695,000 / 3.
the oldest son gets 2 times that plus 5000, so the oldest son gets 2 * 695,000 / 3 + 5000.
put everything under a common denominator and the oldest son gets (2 * 695000 + 15000) / 3 which results in 1,405,000 / 3.
digitize both results and the youngest son gets 231,666.666... and the oldest son gets 468,333.333....
round your answer to the nearest penny and the youngest son gets 231,666.67 and the oldest son gets 468,333.33.
your solution is the younger son gets 231,666.67 rounded to the nearest penny.
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