Question 1092059: problem 1:
Mrs.Davidson bought some apples and oranges for a total of $4.10.The cost of an orange is 50 cents which is 10 cents more than the cost of an apple.If there were a total 0f 9 fruits,find the number of apples and number of oranges Mrs.Davidson bought.
Found 3 solutions by Fombitz, ikleyn, greenestamps: Answer by Fombitz(32388) (Show Source): Answer by ikleyn(52847) (Show Source):
You can put this solution on YOUR website! .
From the condition, the cost of one orange is 50 cents and the cost of one apple is 50 - 10 = 40 cents.
Let x be the number of apples.
40x + 50*(9-x) = 410 cents ====> 40x + 450 - 50x = 410 ====> -10x = 410-450 = -40 ====> x = 4.
Answer. 4 apples and 9-4 = 5 oranges.
There are 3 (three) ways to solve this problem.
1. Writing the system of 2 equations in two unknowns.
2. Using one equation and one unknown (it is what I did in my post)
3. To solve the problem MENTALLY, without using equations.
It is what the tutor @greenestamps did in his post.
See the lessons
- Problem on two-wheel and three-wheel bicycles,
- Problem on animals at a farm and
- Problem on pills in containers
in this site, where similar problems were solved using all three methods.
Answer by greenestamps(13203) (Show Source):
You can put this solution on YOUR website! How about an informal solution....
If all 9 fruits were oranges, the cost would be 9 times 50 cents, a total of $4.50.
But the total cost was $4.10, which is 40 cents less than $4.50.
Since each apple costs 10 cents less than each orange, and since $4.10 is 40 cents less than $4.50, the number of apples must be 40/10 = 4.
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