SOLUTION: A jar contains nickels, dimes, and quarters. There are 105 coins with a total
value of $8.40. If there are 3 more than twice as many dimes as quarters, find
how many of each coin
Algebra.Com
Question 1087815: A jar contains nickels, dimes, and quarters. There are 105 coins with a total
value of $8.40. If there are 3 more than twice as many dimes as quarters, find
how many of each coin are in the jar.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
(1)
(2) ( in cents )
(3)
---------------------------
Multiply both sides of (1) by and
subtract (1) from (2)
(2)
(1)
------------------------------
Plug (3) into this result
and
(3)
(3)
(3)
and
(1)
(1)
(1)
(1)
---------------------------
72 nickels
23 dimes
10 quarters
--------------------
check:
(2)
(2)
(2)
(2)
OK
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