SOLUTION: Please show me the steps on how to do this problem. I forgot how to do it. There are two consecutive numbers, where the sum of the lesser number and three times the greater number

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Question 1082972: Please show me the steps on how to do this problem. I forgot how to do it.
There are two consecutive numbers, where the sum of the lesser number and three times the greater number is 103. What is the greater number?
Found 2 solutions by Theo, MathTherapy:
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
let x equal 1 of the numbers.

since the number are consecutive, then the next number is x + 1.

the sum of the smaller number and 3 times the larger number is 103.

that becomes x + 3 * (x + 1) = 103

simplify to get x + 3x + 3 = 103

combine like terms to get 4x + 3 = 103

subtract 3 from both sides to get 4x = 100

solve for x to get x = 25.

the smaller number is 25.
the larger number is 26.

the sum of the smaller number and 3 times the larger number is equal to 25 + 3 * 26 which is equal to 25 + 78 which is equal to 103.

this confirms the solution is correct.


Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

Please show me the steps on how to do this problem. I forgot how to do it.
There are two consecutive numbers, where the sum of the lesser number and three times the greater number is 103. What is the greater number?
Let the larger number be L

Then smaller = L - 1

We then get: L - 1 + 3L = 103

4L = 103 + 1

4L = 104

L, or larger number = 

That's all.....nothing COMPLEX nor CONFUSING! 

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