SOLUTION: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 40% and the third contains 85% . He wants to use all three solutions to
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Question 1077881: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 40% and the third contains 85% . He wants to use all three solutions to obtain a mixture of 108 liters containing 45% acid, using 2 times as much of the 85% solution as the 40% solution. How many liters of each solution should be used?
The chemist should use _____ liters of 25% solution, _____ liters of 35% solution, and ____ liters of 75% solution.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The first acid solution contains 25% acid, the second contains 40% and the third contains 85% . He wants to use all three solutions to obtain a mixture of 108 liters containing 45% acid, using 2 times as much of the 85% solution as the 40% solution. How many liters of each solution should be used?
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x of 25%
y of 40%
z of 85%
-
Account for the pure acid
Account for the volume
Simpler system in two variables:
Use five times the second equation and subtract from first equation.
-
60 liters of 25%
16 liters of 40%
32 liters of 85%
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