SOLUTION: A collection of half dollars and nickels is worth $13.40. There are 34 coins in all. How many of each are there?

Question 1070059: A collection of half dollars and nickels is worth $13.40. There are 34 coins in all. How many of each are there?

Found 3 solutions by Boreal, stanbon, josgarithmetic:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
x=half dollars
34-x=nickels
.50x+(.05)(34-x)=13.40
.50x+1.70-.05x=13.40
.45x=11.70
x=26 half dollars $13.00
34-x=8 nickels $0.40
Sum to $13.40.
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
A collection of half dollars and nickels is worth $13.40. There are 34 coins in all. How many of each are there?
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Coins:: h + n = 34 coins
Value::50h + 5n = 1340 cents
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Modify for elimination::
10h + 10n = 10*34
10h + n = 268
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Subtract and solve for "n"::
9n = 72
n = 8 (# of nickels)
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h = 34-n = 34-8 = 26 (# of half-dollars)
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Cheers,
Stan H.
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Answer by josgarithmetic(39633)   (Show Source): You can put this solution on YOUR website!
ASSIGN VARIABLES
n, the count of nickels
h, the count of half-dollars

WRITE EQUATIONS

First equation accounts for cents, and second accounts for how many coins.

SOLVE SYSTEM OF EQUATIONS
If multiply both members of the cent-account equation by , then the system is:

-
Use whatever method you know or need.
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