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Tommy can paint a fence in 9 hours. If his friend Huck helps, they can paint the fence in 1 hour. How fast could Huck paint the fence by himself?
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Tommy paints 1/9 of the fence in one hour.
Huck and Tommy together paint 1 fence in one hour.
Hence, Huck paints 1 - (1/9) = (9/9)-(1/9) = 8/9 of the fence per hour.
Thus, Huck can paint the fence in 9/8 hour or hours (1 hr and 7 min 30 sec).
The problem was solved today under this link
https://www.algebra.com/algebra/homework/coordinate/word/Linear_Equations_And_Systems_Word_Problems.faq.question.1065124.html
https://www.algebra.com/algebra/homework/coordinate/word/Linear_Equations_And_Systems_Word_Problems.faq.question.1065124.html
Since you submitted it repeatedly, I copied that solution and slightly edited it to make it more understandable.
It is a typical joint work problem.
For a wide variety of similar solved joint-work problems with detailed explanations see the lessons
- Using Fractions to solve word problems on joint work,
- Solving more complicated word problems on joint work,
- Selected joint-work word problems from the archive
in this site.
Read them and get be trained in solving joint-work problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Rate of work and joint work problems" of the section "Word problems".