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Tickets at a basketball game were $4 for an adult and $2 for a student. The total number of tickets sold was 300.
If the sales of tickets was $800, how many tickets of each were sold?
Thank you!
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Two ways to solve.
Solution 1. Two equations
A + S = 300, (1)
4A + 2S = 800. (2) (the "value" equation)
Divide eq.(2) by 2 (both sides). Rewrite you system as
A + S = 300, (1')
2A + S = 400. (2')
Distract eq.(2') from (1') (both sides). You will get
A = 100.
Answer. 100 adults tickets and 300-100 = 200 student tickets.
Solution 2. One equation
Let "A" be the number of adults' tickets.
Then the number of students' tickets is 300-A.
The value equation is
4A + 2*(300-A) = 800.
Simplify and solve for A.