SOLUTION: A chemist needs 80 milliliters of a 28% solution but has only 19% and 43% solutions available. How many milliliters of each that should be mixed to get the desired solution.
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Question 1061560: A chemist needs 80 milliliters of a 28% solution but has only 19% and 43% solutions available. How many milliliters of each that should be mixed to get the desired solution.
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
0.19x+0.43(80-x) = 0.28(80)
x = 50
you need 50 of the 19% and 30 of the 43%
i ran out of time, email me if you need more details.
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