SOLUTION: A professor started a project with a group of students, 60 % of whom were boys. Due to some unavoidable reasons, six girls couldn't turn up, so the professor had to make some chan

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A professor started a project with a group of students, 60 % of whom were boys. Due to some unavoidable reasons, six girls couldn't turn up, so the professor had to make some chan      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   


Question 105884: A professor started a project with a group of students, 60 % of whom were boys. Due to some unavoidable reasons, six girls couldn't turn up, so the professor had to make some changes in the group. He admitted six boys. In doing so, the percentage of boys in the project increased to 75%. Find the number of boys and girls involved in the project initially.
Answer by ankor@dixie-net.com(12706) About Me  (Show Source):
You can put this solution on YOUR website!
A professor started a project with a group of students, 60% of whom were boys. Due to some unavoidable reasons, six girls couldn't turn up, so the professor had to make some changes in the group. He admitted six boys. In doing so, the percentage of boys in the project increased to 75%. Find the number of boys and girls involved in the project initially.
:
Let t = total number of students, (remains the same)
.6t = number of boys originally
:
(.6t + 6) = actual number of boys (which the problem says became 75%)
:
From all this we have one simple equation:
.6t + 6 = .75t
.6t - .75t = -6
-.15t = -6
t = -6/-.15
t = +40 kids
:
.6 * 40 = 24 boys originally
.4 * 40 = 16 girls "