SOLUTION: one can juice is 30% juice and another is 5% juice. How many liters of each should be mixed togther to get 25liters that is 28%juice

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Question 1050388: one can juice is 30% juice and another is 5% juice. How many liters of each should be mixed togther to get 25liters that is 28%juice
Answer by ikleyn(52915)   (Show Source): You can put this solution on YOUR website!
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one can juice is 30% juice and another is 5% juice. How many liters of each should be mixed togther to get 25liters that is 28%juice
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The equation of the pure juice content is this

0.3x + 0.05*(25-x) = 0.18*25,

where x is unknown volume in liters of the 30% juice.

Simplify and solve:

0.3x + 0.05*25 - 0.05x = 4.5,

0.25x + 1.25 = 4.5  --->  0.25x = 4.5 - 1.25  --->  0.25x = 3.25  --->  x =  = 13.

Answer. 13 liters of the 30% juice and (25-13) = 12 liters of the 5% juice.

For detailed solutions of mixture problems see the lessons
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
    - OVERVIEW of lessons on word problems for mixtures
in this site.

Read them and become an expert in solving mixture word problems.


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