SOLUTION: Solve for µ
[1/( µ - 5)] – [10/( µ
2
– 5µ + 25)] = 1 /( µ + 5)
Algebra.Com
Question 1048231: Solve for µ
[1/( µ - 5)] – [10/( µ
2
– 5µ + 25)] = 1 /( µ + 5)
Answer by ikleyn(52835) (Show Source): You can put this solution on YOUR website!
.
Unreadable.
RELATED QUESTIONS
solve for thw followig equation... (answered by Fombitz)
Solve for b: {{{2b/(5+b)-1/(5-b)=10/(b^2-25)}}}
A) 5
B) {-1/2 , 5}
C) -1/2
D) No... (answered by stanbon)
Solve for x: 5(x – 2)^2 = 3
a. +- 59/25
b. 1/5, 19/5
c. 10+-√15/5
d.... (answered by jim_thompson5910)
Solve for µ
[1/( µ - 5)] – [10/( µ2 – 5µ + 25)] = 1 /( µ + 5)
the 2 after µ is a... (answered by MathLover1)
Solve for: 25(2x-1)=... (answered by Fombitz)
3 / x^2 - 25 = 1 / x + 5 + 2 / x - 5
Solve the equation for the... (answered by mananth)
Solve. 5(x-2)^2=3
a. 1/5 19/5
b. 10+-square root15over 5
c. 10+-square root3... (answered by jim_thompson5910,edjones)
(25-_)×1=5×5
(answered by Alan3354)
10/(x^2-25) - 1/(x-5) = 1 (answered by josgarithmetic,MathTherapy)