SOLUTION: A chemist wants to mix three different solutions to create 100 milliliters of a solution that is 24.5% alcohol.Solution A is 10% alcohol, solution B is 15% alcohol and solution C i

Question 1046990: A chemist wants to mix three different solutions to create 100 milliliters of a solution that is 24.5% alcohol.Solution A is 10% alcohol, solution B is 15% alcohol and solution C is 30% alcohol. The amount of solution A that is used must be twice the amount of solution B that is used.How many milliliters of each solution should the chemist combine?
Found 2 solutions by Boreal, josmiceli:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Let b=x
then a=2x
and c=100-3x
That adds to 100 ml
0.10(2x)+(0.15)(x)+(0.3)(100-3x)=100(0.245)
0.2x+0.15x+30-0.9x=24.5
-0.55x+30=24.5
-0.55x=-5.5
x=10 ml B
2x=20 ml A
100-3x=70 ml C

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
You need to end up with:
ml of alcohol
--------------------
Let the amounts in ml of the 3 solutions =
, , and
given:

--------------
(1) ml
(2)
------------------------------------
(1)
(2)
(2)
(2)
-------------------------------
Multiply both sides of (1) by and
and subtract (2) from (1)
---------------------------
(1)
(2)
--------------------------

and

and
(1)
(1)
(1)
------------------------
The chemist needs:
20 ml of A
10 ml of B
70 ml of C
--------------
check:
(2)
(2)
(2)
(2)
OK
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