SOLUTION: A ball is thrown into the air with an initial velocity of 64 feet per second from a height of 192 feet. After how many seconds will the ball return to the ground and have a height

Question 1040847: A ball is thrown into the air with an initial velocity of 64 feet per second from a height of 192 feet. After how many seconds will the ball return to the ground and have a height of zero again?
Found 2 solutions by ankor@dixie-net.com, ikleyn:
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
A ball is thrown into the air with an initial velocity of 64 feet per second from a height of 192 feet.
After how many seconds will the ball return to the ground and have a height of zero again?
:
Using the equation:
t = time
-16t^2 force of gravity downward,
64t = initial velocity upward,
192 = initial height
:
-16t^2 + 64t + 192 = 0
simplify, divide equation by -16
t^2 - 4t - 12 = 0
Factors easily to
(t-6)(t+2) = 0
the positive solution
t = 6 sec to return to the ground
:
:
see if that works
-16(6^2) + 64(6) + 192 =
-576 + 384 + 192 = 0

Answer by ikleyn(52784)   (Show Source): You can put this solution on YOUR website!
.
See the lessons
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform
    - OVERVIEW of lessons on a projectile thrown/shot/launched vertically up
in this site, where similar problems were solved.

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