SOLUTION: Sheila, Janice and Karen working together at the same rate can complete a job in 3 1/3 days. Working at the same rate, how much of the job could Janice and Karen do in one day?

Question 1034203: Sheila, Janice and Karen working together at the same rate can complete a job in 3 1/3 days. Working at the same rate, how much of the job could Janice and Karen do in one day?
Thanks; I'm familiar with the standard 1/t-1 + 1/t-2 = 1/x where the first two are the times of those individuals and x is their time working together, but I don't know how to adapt this formula to the problem I've written. If you have a reference for that problem, so I could review it further, I'd really appreciate it. Garrett
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Sheila, Janice and Karen working together at the same rate can complete a job in 3 1/3 days. Working at the same rate, how much of the job could Janice and Karen do in one day?
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Let rate for each of Sh, Ja, and Ka be 1/t
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Together rate = 1/(3 1/3) = 1/(10/3) = 3/10
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3(1/t) = 3/10
1/t = 1/10
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t = 10 days (time each would take to do the job alone)
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Ja and Ka rate = (2(1/10) = 1/5 job/day
Cheers,
Stan H.
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