SOLUTION: We have three different mixtures of antifreeze and water. One mixture is 15% antifreeze, the second is 20% antifreeze and the third is 25% antifreeze, We would like to have 350 q

Question 1030915: We have three different mixtures of antifreeze and water. One mixture is 15% antifreeze, the second is 20% antifreeze and the third is 25% antifreeze, We would like to have 350 quarts of 19.5% antifreeze and use twice as much of the second mixture as the combined total of the first and third. How much of each mixture must we use?
Need three linear equations
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!

L     low     15%
m     medium  20%
h     high    25%

Twice as much of the 20% as the combined quantities of the 15% and 25%.

ACCOUNT VOLUME OF MIX
, in unit of quarts.

ACCOUNT CONCENTRATION OF MIX
, both members in percent.

Next in the process should be substitute for m in both accounting equations, and simplify each of these equations; and solve the resulting two-variable system of the two equations, using variables, L and h.
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