SOLUTION: the larger of two numbers is 4 less than fives times the smaller. when the smallest number is subtracted from the larger, the difference is 4. find the two numbers
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Question 1022428: the larger of two numbers is 4 less than fives times the smaller. when the smallest number is subtracted from the larger, the difference is 4. find the two numbers
Found 2 solutions by addingup, MathTherapy:
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
x-4 = 5y (1)
x-y = 4 (2)
~~~~~~~~~~~~~~~~~~~~~
In equation (1) subtract 5y and add 4 on both sides:
x-5y = 4 Now we have a new equation, let's call it (3)
In equation (2) multiply all times -5:
-5x+5y = -20 Add this equation to (3)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
x-5y = 4
+
-5x+5y = -20
-------------
-4x = -16 divide both sides by -4 and remember -/- = +
x = 4 Now let's find y:
x-y = 4
4-y = 4
4 = 4+y
0 = y
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The problem has two equations:
x-4 = 5y (1)
x-y = 4 (2)
Let's try our numbers:
4-4 = 5(0); 0 = 0 this one is correct. Next:
4-0 = 4 This is also correct. We have the correct answers
Answer by MathTherapy(10551) (Show Source): You can put this solution on YOUR website!
the larger of two numbers is 4 less than fives times the smaller. when the smallest number is subtracted from the larger, the difference is 4. find the two numbers
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