# SOLUTION: crystal sells coffee. her special blend is a combination of french roast @ \$7.50 a lb. and kona deluxe @ \$11.50 a lb. how many pounds of kona should she mix with 12 lbs. of french

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 Question 101111: crystal sells coffee. her special blend is a combination of french roast @ \$7.50 a lb. and kona deluxe @ \$11.50 a lb. how many pounds of kona should she mix with 12 lbs. of french roast to get a blend to be sold for \$10.00 a lb.?Found 2 solutions by checkley71, stanbon:Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!7.5*12+11.5X=10(12+X) 90+11.5X=120+10X 11.5X-10X=120-90 1.5X=30 X=30/1.5 X=20 LBS OF KONA IS NEEDED. PROOF 7.5*12+11.5*20=10(12+20) 90+230=10(32) 320=320 Answer by stanbon(57289)   (Show Source): You can put this solution on YOUR website!crystal sells coffee. her special blend is a combination of french roast @ \$7.50 a lb. and kona deluxe @ \$11.50 a lb. how many pounds of kona should she mix with 12 lbs. of french roast to get a blend to be sold for \$10.00 a lb.? -------------- Amt. of french is 12 lbs; value of this is 7.50*12 = 90 dollars ------------ Let amt of kona be x lbs; value of this is 11.50x dollars --------------- Amt of mixture is 12+x lbs; value is 10(12+x)=120+10x dollars ---------------------- EQUATION: 90 + 11.50x = 120+10x 1.5x = 30 x = 20 lbs. (Amount of kona that must be added to make the blend) ============ Cheers, Stan H.