SOLUTION: A drive in movie theater charges $3.50 per car and has already taken $350. Write an inequality you could use to determine how many more cars the drive in needs to earn in excess of

Question 1005806: A drive in movie theater charges $3.50 per car and has already taken $350. Write an inequality you could use to determine how many more cars the drive in needs to earn in excess of $500
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
revenue = price per car * number of cars.

let r = revenue
let p = price per car
let c = number of cars.

you want revenue to be greater than 500.

the inequality would be:

r > 500

since you already generate 350 dollars in revenue, then subtract that from 500 to get how much more revenue you need.

you get:

r > 150

you need to generate additional revenue greater than 150.

since r = p * c, you can replace r in this inequality with p * c to get:

p * c > 150

since p is the price per car which is equal to 3.50, you can replace p with 3.50 to get:

3.50 * c > 150

solve for c to get c > 150 / 3.50 which becomes:

c > 42.85714286

since the number of cars has to be an integer, you get:

c >= 43.

if the number of additional cars is 43 or more, you will make more than 150 in additional revenue.

42 * 3.50 = 147 which is less than 150.
43 * 3.50 = 150.5 which is greater than 150.

the formula holds true.

your inequality is 3.50 * c > 150.

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