Question 81760: please help.
solve the system by substitution.
5x+4y=-2
y=4x+10
20x-4y=-8
y=2+5x
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! 5x+4y=-2
y=4x+10
5x+4y = -2
5x+4(4x+10) = -2
5x+16x + 40=-2
21x =-2-40
21x=-42
x=-2
y=4x+10
y=4(-2)+10
y=-8+10
y=2
Check in the other equation:
5x+4y=-2
5(-2)+4(2)=-2
-10+8=-2 It checks!!
Now, you solve your other problem just like this one!!
R^2 at SCC
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