SOLUTION: Mr. McKelvey finds that flying with the wind he can travel 1188 miles in 6 hours. However, when flying against the wind, he travels only 2/3 of the distance is the same amount of t

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Lessons  -> Linear Equations Lesson -> SOLUTION: Mr. McKelvey finds that flying with the wind he can travel 1188 miles in 6 hours. However, when flying against the wind, he travels only 2/3 of the distance is the same amount of t      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 53486: Mr. McKelvey finds that flying with the wind he can travel 1188 miles in 6 hours. However, when flying against the wind, he travels only 2/3 of the distance is the same amount of time.
Find the speed of the plane in still air and the wind speed.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
1188/6=198 mph with the wind.
(1188*2/3)/6=792/6=132 mph against the wind
198-132=66 is the difference thus the wind is 66/2=33 mph.
proof 198-33=165 & 132+33=165 which is the speed of the plane in still air.