SOLUTION: For all nonzero r.t. and z values, 16r(cubed)tz(to the 5th power) -------------------------------= ??

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Question 123018: For all nonzero r.t. and z values, 16r(cubed)tz(to the 5th power)
-------------------------------= ??
-4rt(cubed)z(squared)
please explain how you got it
Answer by stanbon(48567) About Me  (Show Source):
You can put this solution on YOUR website!
16r(cubed)tz(to the 5th power)
------------------------------= ??
-4rt(cubed)z(squared)
====================================
[16r^3tz^5] / [-4rt^3z2]
-----------------
= -4r^2z^3/t^2
=========================
Cheers,
Stan H.