You can
put this solution on YOUR website!subtracting the first equation from the third gives 5y-4z=10
subtracting 2 times the first equation from the second gives 9y+3z=18
(4/3)(9y+3z=18) ... 12y+4z=24 ... adding 5y-4z=10 gives 17y=34 ... y=2
x-(3)*(2)=0 ... x=6
6+2(2)-4z=10 ... -4z=0 ... z=0
