SOLUTION: the length of a room is two and half time its width. if the perimeter of the floor of the room is 70m find the length & width of the room.

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: the length of a room is two and half time its width. if the perimeter of the floor of the room is 70m find the length & width of the room.      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 99687: the length of a room is two and half time its width. if the perimeter of the floor of the room is 70m find the length & width of the room.
Answer by doukungfoo(195) About Me  (Show Source):
You can put this solution on YOUR website!
Ok first thing:
the perimeter of a rectangle is equal to the sum of all its sides.
this can be expressed as 2 times the length plus 2 times the width.
lets called the width x
Given: the length of a room is two and half times its width.
so the length equals %282%261%2F2%29x
Given: perimeter equals 70 meters
Now we have everything we need to write a formula to solve for x (width)
2%28length%29%2B2%28width%29=70
2%28%282%261%2F2%29x%29%2B2%28x%29=70
5x%2B2x=70
7x=70
x=10
So the width = 10 meters
To find length use
2%261%2F2%28x%29=length
2%261%2F2%2810%29=length
25=length
So the length = 25 meters
To check use the original formula
2%28length%29%2B2%28width%29=70
2%2825%29%2B2%2810%29=70
50%2B20=70
70=70
that is it