SOLUTION: Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?      Log On

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Question 77716This question is from textbook Algebra Structure and Method
: Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?This question is from textbook Algebra Structure and Method

Answer by stanbon(57337) About Me  (Show Source):
You can put this solution on YOUR website!
Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?
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Let the number of coins each has be "x".
Value of Luis's dimes = 10x cents
Value of Julia's quarters = 25x cents
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EQUATION:
Julia value - Luis value = 180 cents
25x-10x=180
15x=180
x = 12 (number of coins each has)
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Cheers,
Stan H.