# SOLUTION: Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has \$1.80 more than Luis does, how many coins does each have?

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 Click here to see ALL problems on Linear-systems Question 77716This question is from textbook Algebra Structure and Method : Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has \$1.80 more than Luis does, how many coins does each have?This question is from textbook Algebra Structure and Method Answer by stanbon(57337)   (Show Source): You can put this solution on YOUR website!Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has \$1.80 more than Luis does, how many coins does each have? ---------------- Let the number of coins each has be "x". Value of Luis's dimes = 10x cents Value of Julia's quarters = 25x cents --------- EQUATION: Julia value - Luis value = 180 cents 25x-10x=180 15x=180 x = 12 (number of coins each has) ========== Cheers, Stan H.