SOLUTION: How would I find the solutions to the equation x^2+2x+5=0

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Question 67112This question is from textbook 0-534-49449-8
: How would I find the solutions to the equation x^2+2x+5=0This question is from textbook 0-534-49449-8

Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
The given equation is:

x%5E2+%2B+2x+%2B+5+=+0

The last constant term is 5, this can be factored as 5 * 1

Neither addtion of these two factors nor the subtraction gives us the middle term +2.

Hence, to find the roots of the equation, we use the quadratic formula. This is given by:

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

From the given equation, we find the values of a, b and c from the given equation.

Hence, a = 1, b = 2 and c = 5. Substitute these values in the above formula.


x+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A1%2A5+%29%29%2F%282%2A1%29+


x+=+%28-2+%2B-+sqrt%28+4-20+%29%29%2F%282%29

x+=+%28-2+%2B-+sqrt%28-16%29%29%2F2

x+=+%28-2+%2B-+4i%29%2F2

x+=+-1+%2B+-+2i

Hence, the answer.

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