You can
put this solution on YOUR website!3x+5y=1
FIRST PUT THE EQN. IN STD. FORM
Y = MX + C
THAT IS KEEP ONLY Y..[NOTE ONLY +1*Y IT SHOULD BE] ON LHS AND TRANSFER X AND CONSTANT TERMS TO RHS.
THEN M THE COEFFFICIENT OF X IS THE SLOPE AND CONSTANT TERM IS THE Y INTERCEPT OR CALLED THE INTERCEPT IN SHORT
HERE WE GET
5Y=-3X+1
Y=-3X/5 +1/5
HENCE M= SLOPE = -3/5
AND INTERCEPT = 1/5
4x-5y=2 ....SIMILARLY
M=4/5......INTERCEPT = -2/5
2x+3y+5=0
M= -2/3..INTERCEPT = -5/3
Then instructions says to find the slope of the line.
I tried working these problems but I am not fully understanding what to do first. Can you give me a break down step by step how to do these problems. thanks so much for your help
You can
put this solution on YOUR website!In each case, do whatever you have to do to get the
equations in the form
where m = slope
subtract 3x from both sides
divide both sides by 5
answer
You do roughly the same to the other equations
You can
put this solution on YOUR website!QUESTION;
Find the slope of given equations.
ANSWER;
The equation of the line can be written in slope-intercept form as
y = mx+b where 'm' is the slope of the equation and b is the 'y' intercept.
To find the slope of the equation, first of all rewrite the given equation in standard form, that is y = mx + c
1.3x+5y=1
==>3x+5y=1
Subtract 3x from both sides of the equation,
==> 3x + 5y -3x = 1-3x
==> 5y = 1-3x
Divide both sides by 5
==> 5y/5 = ( 1-3x )/5
==> y = 1/5 - 3x/5
==> y = 1/5 + (-3/5)x
==> y = (-3/5)x + 1/5, which is of the form, y = mx + c
where m = -3/5
Therefore slope of the equation is -3/5
2. 4x - 5y = 2
As in above proceed,
4x - 5y -4x = 2 -4x
==> -5y = 2- 4x
==> -5y/-5 =(2-4x)/-5
==> y = 2/-5 - 4x/-5
==> y = (-2/5) + (4/5)x
==> y = (4/5)x + ( -2/5)
which is of the form, y = mx +c
so here slope is = 4/5
3. 2x +3y +5 = 0
2x + 3y + 5 - 5 = 0 - 5
2x + 3y = -5
2x + 3y - 2x = -5 - 2x
3y = -5 - 2x
3y/3 = -5/3 -2x/3
y = (-5/3) + ( -2/3)x
Therefore, slope = (-2/3)
Regards.
praseenakos@yahoo.co.in
