You can
put this solution on YOUR website!You have 2 straight lines. The best way to get an
idea what they look like is to convert the equations
from the standard form ( as they now are ) into
the slope-intercept form
---------------------
(1)
and
(2)
---------------------
(1) and (2) are now in the form
where
= slope and
= y - intercept
---------------------
In (1),
In (2),
Both slope are negative, which means they go from
upper left to lower right on the graph, opposite to
what a positive slope does
---------------------
gives you a point for free on each line. It
is the y-intercept point which is (0,b), or
(0, 2) for equation (1)
(0,6) for equation (2)
--------------------
Now you just need 1 other point for both lines, and
since 2 points determine a line, you can draw
each line. Where the lines intersect is the solution
to the system of lines
--------------------
To find the other point, just plug in any value for
, and read off the value for
For example:
(1)
I'll pick
(1)
(1)
So, I have the point (1,0)
and
(2)
I'll pick
(2)
(2)
(2)
So, I have the point (2,0)
---------------------
Now you have this information about the lines:
Line (1):
(0,2)
(1,0)
----------
Line (2):
(0,6)
(2,0)
----------
And that's all you need
You can
put this solution on YOUR website!
Hi,
Solve the system by putting each of their graphs on the same graph
the point they intersect at: (-2,6) is the solution for this system
If You are having difficulty graphing each of the linear equations:
find at least 2 (x,y)points for each and connect pair of the 2 points with their
respective line
2x+y=2 x = 0 ⇒ y = 2, y = 0 ⇒ x = 1 (0,2) and (1,0) on this line
6x+4y=12 x = 0 ⇒ y= 3, y = 0 ⇒ x = 2 (0,3) and (2,0) on this line
