# SOLUTION: Hi, I have a word problem. And it says that I have to assume that the exercise describes a linear relationship. ok... here it is. A vendor has learned that, by pricing hot dogs

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Hi, I have a word problem. And it says that I have to assume that the exercise describes a linear relationship. ok... here it is. A vendor has learned that, by pricing hot dogs       Log On

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 Question 45804: Hi, I have a word problem. And it says that I have to assume that the exercise describes a linear relationship. ok... here it is. A vendor has learned that, by pricing hot dogs at \$1.00, sales would reach 102 hot dogs per day. Raising the price to \$1.50 will cause the sales to fall to 78 hot dogs per day. Let y be the number of hotdogs the vendor sells at x dollars each. Write a linear equation that models the number of hot dogs sold per day when the price is x dollars each. In my work I keep getting 48x but Im not sure how. I may be negative, I don't know. And I'm getting both 54 and 150 to add on to it in the equation but again, I'm not sure. THANK YOU!Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!THE TWO POINTS TO GRAPH THE PROBLEM ARE (100,102)(150,78) THUS THE SLOPE OF THE LINE IS (78-102)/(150-100) OR -24/50 OR -.48 THEN THE EQUATION FOR THIS LINE IS Y=-.48X+B NOW REPLACING Y & X BY ONE OF THE POINTS WE FIND THE VALUE OF B THUS 102=-.48*100+B OR 102=-48+B OR 102+48=B OR B=150 THUS THE EQUATION FOR THIS LINE/RELATIONSHIP IS Y=-.48X+150