SOLUTION: 2x-y+z=10 4x+2y-3z=10 x-3y+2z=8 solve for x, y,z i have so far 2x-y+z=10 4x+2y-3z=10 multiply the first equation by 2 which gives 4x-2y+2z=20 am i

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: 2x-y+z=10 4x+2y-3z=10 x-3y+2z=8 solve for x, y,z i have so far 2x-y+z=10 4x+2y-3z=10 multiply the first equation by 2 which gives 4x-2y+2z=20 am i       Log On

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Question 44821: 2x-y+z=10
4x+2y-3z=10
x-3y+2z=8
solve for x, y,z
i have so far
2x-y+z=10
4x+2y-3z=10
multiply the first equation by 2 which gives
4x-2y+2z=20
am i on the right track
Answer by stanbon(48558) About Me  (Show Source):
You can put this solution on YOUR website!
Yes, then subtract it from the 2nd equation to eliminate
the x-terms.
Cheers,
Stan H.