# SOLUTION: how do i set up the problem : Audrey has 32 dimes and quarters in her piggy bank with a total value of 6.50. How many of the coins are dimes and how many are quarters? I need

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 Question 364533: how do i set up the problem : Audrey has 32 dimes and quarters in her piggy bank with a total value of 6.50. How many of the coins are dimes and how many are quarters? I need to write 2 equations and solve by addition methodFound 2 solutions by ewatrrr, nerdybill:Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website!``` Hi, I need to write 2 equations and solve by addition method in that case, let x = number of dimes and y = number of quarters x + y = 32 10x + 25y = 650 cents Multiplying both sides of the first equation by -25 to eliminate y -25x -25y = 32*(-25) 10x + 25y = 650 cents -15x = -150 x = 10, the enumber of dimes the quarters would be 22 (32-10) checking our answer 10*10 + 22*25 = 100 + 550 = 650cents Or \$6.50 ```Answer by nerdybill(6948)   (Show Source): You can put this solution on YOUR website!Audrey has 32 dimes and quarters in her piggy bank with a total value of 6.50. How many of the coins are dimes and how many are quarters? I need to write 2 equations and solve by addition method . Let x = number of dimes and y = number of quarters . From: "Audrey has 32 dimes and quarters in her piggy bank" x + y = 32 (equation 1) . From: "total value of 6.50" .10x + .25y = 6.50 (equation 2) . Using the "addition method", to eliminate x, we multiply both sides of equation 1 by -.10 and "add" the two equations together: -.10x - .10y = -3.2 .10x + .25y = 6.50 ---------------------- .15y = 3.3 y = 22 (number of quarters) . Substitute the above value of y back into equation 1 to find x: x + y = 32 x + 22 = 32 x = 32-22 x = 10 (number of dimes)