# SOLUTION: A store bought a \$1000 shipment of sweaters and offered them for sale after a \$15 markup on each sweater. All but 10 sweaters were sold, and the store made a \$400 profit on the swe

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: A store bought a \$1000 shipment of sweaters and offered them for sale after a \$15 markup on each sweater. All but 10 sweaters were sold, and the store made a \$400 profit on the swe      Log On

 Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo . Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Linear Solvers Practice Answers archive Word Problems Lessons In depth

 Question 77572: A store bought a \$1000 shipment of sweaters and offered them for sale after a \$15 markup on each sweater. All but 10 sweaters were sold, and the store made a \$400 profit on the sweaters. How many sweaters did the store buy?Answer by stanbon(57203)   (Show Source): You can put this solution on YOUR website!A store bought a \$1000 shipment of sweaters and offered them for sale after a \$15 markup on each sweater. All but 10 sweaters were sold, and the store made a \$400 profit on the sweaters. How many sweaters did the store buy? ----------- Let "x" be the number of sweaters bought. Paid price per sweater = 1000/x Selling price per sweater = 1000/x + 15 ------------ EQUATION: (number of sweaters sold)(selling price) = 1000 +400 (x-10)((1000/x)+15)=1400 1000+15x-10000/x-150 = 1400 15x-(10000/x)=550 15x^2-10000=550x 15x^2-550x-10000=0 3x^2-110x-2000=0 x=[110+-sqrt(12100-4*3*-2000)]/6 x=[110+-sqrt(36100)]/6 x=50 (# of sweaters bought) ========== Cheers, Stan H.