# SOLUTION: The width of a rectangle is 3 ft. less than the length. The area is 4 ft^2. Find the length and the width. For some reason I cannot figure this out and I need it for a test can

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: The width of a rectangle is 3 ft. less than the length. The area is 4 ft^2. Find the length and the width. For some reason I cannot figure this out and I need it for a test can      Log On

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 Click here to see ALL problems on Linear Equations And Systems Word Problems Question 635050: The width of a rectangle is 3 ft. less than the length. The area is 4 ft^2. Find the length and the width. For some reason I cannot figure this out and I need it for a test can anyone help quickly Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!Length =L Width=W=L-3 Area=A=4ft^2 Area= Length*Width A=L*W Solve for L OR OR (unacceptable) so L=4 Length =L = 4 ft Width=W=L-3 = 4-3 = 1ft