# SOLUTION: Four oranges and five apples cost \$2.00. Three oranges and four apples cost \$1.56. Find the cost of an orange and the cost of an apple.

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: Four oranges and five apples cost \$2.00. Three oranges and four apples cost \$1.56. Find the cost of an orange and the cost of an apple.      Log On

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 Click here to see ALL problems on Linear Equations And Systems Word Problems Question 37656This question is from textbook : Four oranges and five apples cost \$2.00. Three oranges and four apples cost \$1.56. Find the cost of an orange and the cost of an apple.This question is from textbook Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!4OR+5A=200 & 3OR+4A=156 IF WE MULTIPLY THE FIRST EAUATION BY 3 AND THE SECOND BY 4 WE GET 12OR+15A=600 & 12OR+16A=624 AND SUBTRACT THESE TWO WE GET ------------------ 0OR-1A=-24 OR A=24 THEN 4OR+5*24=200 OR 4OR+120=200 OR 4OR=80 OR OR=80/4 OR OR=20 PROOF 4*20+5*24=200 OR 80+120=200 OR 200=200 & 3*20+4*24=156 OR 60+96=156 OR 156=156