# SOLUTION: A dehydrated patient needs a 3.82% saline IV. Unfortunately, the hospital only has bags of 4% and 3% saline solutions. How many liters of each of these solutions should be mixed to

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 Click here to see ALL problems on Linear Equations And Systems Word Problems Question 354752: A dehydrated patient needs a 3.82% saline IV. Unfortunately, the hospital only has bags of 4% and 3% saline solutions. How many liters of each of these solutions should be mixed together to yield 5 liters of the desired concentration? So far I've come up with this: x= 4% solution; y= 3% solution x + y = 5 4x + 3(5-x) = 3.82 4x + 15 -3x = 3.82 subtracting 15 from both sides 1x = -11.18 x= -11.18Found 2 solutions by stanbon, scott8148:Answer by stanbon(57377)   (Show Source): You can put this solution on YOUR website!A dehydrated patient needs a 3.82% saline IV. Unfortunately, the hospital only has bags of 4% and 3% saline solutions. How many liters of each of these solutions should be mixed together to yield 5 liters of the desired concentration? So far I've come up with this: x= 4% solution; y= 3% solution --------- Quantity Eq::: x + y = 5 liters Salt Eq::::::::4x + 3(5-x) = 3.82*5 4x + 15 -3x = 19.1 x = 4.1 liters (amt. of 4% solution needed in the mixture) y = 5-4.1 = 0.9 liters (amt of 3% solution needed in the mixture) -------------------------- Cheers, Stan H. ========== Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!4x + 3(5-x) = 3.82 * 5 ___ this should get you to the answer