# SOLUTION: Please help me solve this: The perimeter of a rectangle is 24 centimeters. The length of the rectangle is four more than the width. What is the length of the rectangle? 4

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 Question 342391: Please help me solve this: The perimeter of a rectangle is 24 centimeters. The length of the rectangle is four more than the width. What is the length of the rectangle? 4x+x=24? I having difficulty with this subject. LisaFound 2 solutions by jim_thompson5910, MathTherapy:Answer by jim_thompson5910(28715)   (Show Source): You can put this solution on YOUR website!The perimeter of a rectangle with length L and width W is . Since "The length of the rectangle is four more than the width" we know that . In addition, because "The perimeter of a rectangle is 24 centimeters" we can say that . So this means that the equation is . Let me know if that helps. If you need more help, email me at jim_thompson5910@hotmail.com Also, feel free to check out my tutoring website Jim Answer by MathTherapy(1483)   (Show Source): You can put this solution on YOUR website!The perimeter of a rectangle is 24 centimeters. The length of the rectangle is four more than the width. What is the length of the rectangle? Let the length of the rectangle be L Then its width = L - 4, since the length of the rectangle is four more than the width Perimeter of any rectangle = 2L + 2W. Since the length and width of this rectangle = L and L - 4, respectively, and since its perimeter is 24 centimeters, then we can say that: 2L + 2(L - 4) = 24 2L + 2L - 8 = 24 4L = 24 + 8 4L = 32 L, or length = or centimeters.