SOLUTION: Jorge wishes to make 150 pounds of coffee blend that can be sold for $8 per pound. The blend will be a mixture of coffee worth $6 per pound and coffee worth $12 per pound. How many

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Jorge wishes to make 150 pounds of coffee blend that can be sold for $8 per pound. The blend will be a mixture of coffee worth $6 per pound and coffee worth $12 per pound. How many      Log On


   

Question 241496: Jorge wishes to make 150 pounds of coffee blend that can be sold for $8 per pound. The blend will be a mixture of coffee worth $6 per pound and coffee worth $12 per pound. How many pounds of each kind of cofee whould be used in the mixture?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
12x+6(150-x)=8*150
12x+900-06x=1,200
6x=1,200-900
6x=300
x=300/6
x=50 lbs. of $12 coffee is used.
150-50=100 lbs. of $6 coffee is used.
Proof:
12*50+6*100=1,200
600+600=1,200
1,200=1,200