# SOLUTION: A number differs from it's square by the average of the number and it's square I sent the wrong email before

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 Question 22674: A number differs from it's square by the average of the number and it's square I sent the wrong email beforeAnswer by stanbon(57307)   (Show Source): You can put this solution on YOUR website!Let "x" be the number. It's square is x^2 The average of the number and its square is (x+x^2)/2 Equation: x-x^2 = (x+x^2)/2 2x -2x^2 = x+x^2 3x^2-x=0 x(3x-1)=0 x =0 or x = 1/3 Cheers, Stan H.