SOLUTION: A company has a work force of 21 men that produces two types of top end cabinets.
Cabinet A is limited to 150 cabinets per day
Takes 6 person days to produce 100
Has a profit
Question 183018: A company has a work force of 21 men that produces two types of top end cabinets.
Cabinet A is limited to 150 cabinets per day
Takes 6 person days to produce 100
Has a profit of 1800 per 100
Cabinet B is limited to 200 cabinets per day
Requires 9 person days to produce 100
Has a profit of 2400 per 100
I'm really struggling to find the algebraic formula. I've tried spreading the staff across both products and calculating the man hours available and required etc but I just seem to go in circles.
I know I need 3 Lines on my graph so 3 constraints are required as otherwise the feasible domain wont be found but I'm still going in circles.
Any help will be greatly appreciated. Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = number of men who worked on cabinet A
Let = number of men who worked on cabinet B
Given:
It takes 6 person-days to make 100 of A
So, it takes 6 persons 1 day to make 100 of A
The profit is 1800 /100 of A
--------------------
It takes 9 person-days to make 100 of B
So, it takes 9 persons 1 day to make 100 of B
The profit is 2400 / 100 of B
I may be wrong with this- it's all I could
come up with
