SOLUTION: farmer Jones owes farmer brown 10 dollars. neither has any cash, but Jones has 14 cows, which he values at 185 dollars each. he suggests paying his debt in cows, with brown making

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: farmer Jones owes farmer brown 10 dollars. neither has any cash, but Jones has 14 cows, which he values at 185 dollars each. he suggests paying his debt in cows, with brown making       Log On


   

Question 149531: farmer Jones owes farmer brown 10 dollars. neither has any cash, but Jones has 14 cows, which he values at 185 dollars each. he suggests paying his debt in cows, with brown making change by giving Jones some of his pigs at 110 dollars each. is this possible? how?
Answer by rajagopalan(174) About Me  (Show Source):
You can put this solution on YOUR website!
You have to build a cost table
no pig cow
1 110 185
2 220 370
3 330 555
4 440 740
5 550 925
6 660 1110
7 770 1295
8 880 1480
9 990 1665
10 1100 1850
11 1210 2035
...
if you can see the cost table you can find 6 cows cost 1110 and 10 pigs cost 1100.
In this way they can settle their debt.
Resullt:
Jones gives 6 Cows to Brown ..Worth $ 1110
Brown gives 10 pigs to Jones ..worth $1100
Difference 1110-1100=$ 10
Okay