Question 137387: How would i solve these two word problems???
1)An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.
2)Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 2)An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away.
The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.
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Express DATA:
Distance = 50 miles : Rate = 2x mph ; time = 50/2x
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Local train DATA:
Distance = 50 miles ; Rate = x mph ; time = 50/x
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EQUATION:
local train time - express train time = 1 hr
50/x - 50/2x = 1
Multiply thru by 2x to get:
100 - 50 = 2x
50 = 2x
x = 25 mph ( speed of the local train)
2x = 50 mph ( speed of the express)
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Joe has a collection of nickels and dimes that is worth $5.65.
If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45.
How many dimes does he have?
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EQUATIONS:
5n + 10d = 565 cents
5(n+8) + 10(2d) = 1045
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5n + 10d = 565
5n + 20d = 1005
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Subtract 1st from 2nd to get:
10d = 440
d = 44 (# of dimes)
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Substitute into 5n+10d=565 to solve for "n"
5n+10*44 = 565
5n + 440 = 565
5n = 125
n = 25 (# of nickels)
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cheers,
Stan H.
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