Question 120672: Tickets for a train excursion were $120 for a sleeping
room, $80 for a berth, and $50 for a coach seat. The total ticket sales were $8600.
If there were 20 more berth tickets sold than sleeping room tickets and 3 times as
many coach tickets as sleeping room tickets, how many of each type of ticket were
sold?
So, I came up with a few equations and none of them are right. So far I have (x+120)+20(80x) +3x(x+120)=8600
I know I am way off.
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Let x = number of sleeping room tickets @ $120
x+20 = number of berth tickets @ $80
3x= number of coach tickets @ $50
The equation will be
120(x) + 80(x+20) + 50(3x) = 8600
Try this and see if it works out for you!! Let me know if you need to see this solved!!
Please see my website for additional help with word problems. Click on my tutor name "rapaljer" anywhere in algebra.com, and look for "MATH IN LIVING COLOR". Go to Basic Algebra, and look in Chapter 1 for the sections on Word Problems. I also have some more challenging problems in Intermediate Algebra, Chapter 1. I have a LOT of resources, including LOTS of practice tests with detailed solutions sheets for all levels of math.
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