SOLUTION: HELP!!!! Here's my problem that escapes me: When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: HELP!!!! Here's my problem that escapes me: When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of       Log On


   

Question 120304: HELP!!!! Here's my problem that escapes me:
When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?
Thanks in advance for your help.
Joanne
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x="tens digit" and y="units digit"

"When the digits of a two-digit number are reversed, the new number is 9 more than the original number"
__ 10y+x=10x+y+9

"the sum of the digits of the original number is 11"
__ x+y=11

x=11-y __ substituting gives 10y+(11-y)=10(11-y)+y+9 __ 9y+11=119-9y __ 18y=108